0.02x^2+0.1-2=0

Solution for 0.02x^2+0.1-2=0 equation:

0.02x^2+0.1-2=0

We add all the numbers together, and all the variables

0.02x^2-1.9=0

a = 0.02; b = 0; c = -1.9;
Δ = b2-4ac
Δ = 02-4·0.02·(-1.9)
Δ = 0.152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.152}}{2*0.02}=\frac{0-\sqrt{0.152}}{0.04}
=-\frac{\sqrt{}}{0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.152}}{2*0.02}=\frac{0+\sqrt{0.152}}{0.04}
=\frac{\sqrt{}}{0.04}
$